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Rate of Effusion Calculator

Compare gas effusion rates from molar masses using Graham’s law.

By ChemistryCalc•Updated October 28, 2026•References
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Results update as you type. Choose units beside a measurement; changing units converts the current value.

reference rate units

On this pageCalculatorHow to useFormula & methodWorked exampleWhy lighter particles have a larger rateDistinguish effusion from bulk mixingFrequently asked questionsRelated calculatorsSources

01 Set up your calculation

  1. Enter the molar masses of the two gases.
  2. Enter a measured reference rate for gas B, or leave one to compare relative rates.
  3. Compare rates for gases under the same temperature and comparable effusion conditions.

02 The relationship

rA/rB = √(MB/MA). For equal amounts, tA/tB = √(MA/MB).

For the assumptions behind these results, read the explanation below. You can also explore Molar Mass and Molar Mass of Gas.

WORKED EXAMPLE

Follow the numbers

For gases with molar masses 4 and 16 g/mol, rA/rB = √(16/4) = 2. Gas A effuses twice as fast and needs half the time for the same amount.

03 Why lighter particles have a larger rate

At the same temperature, lighter gas particles have greater characteristic molecular speeds than heavier particles. Under the assumptions of effusion through a very small opening, the relative escape rate follows the inverse square root of molar mass.

The ratio is dimensionless. If you supply a reference rate in moles per minute, the predicted rate uses moles per minute; the tool does not infer a unit from the number alone.

04 Distinguish effusion from bulk mixing

Effusion concerns escape through an opening small enough for individual molecular motion to control passage. Diffusion through another gas also depends on collisions, concentration gradients, and geometry. A room-scale mixing time cannot be predicted from the molar-mass ratio alone.

Keep temperature, pressure, and apparatus conditions comparable. A bulk leak, pressure-driven flow, or changing gas mixture may require a different transport model.

Questions from the notebook

Why is the molar-mass ratio reversed?

Rate increases as molar mass decreases, so MA appears in the denominator when calculating rA/rB.

Can this give an absolute rate without a reference?

No. It gives a relative rate; apparatus and conditions set the absolute scale.

Can I compare effusion times?

Yes. For equal gas amounts under matching conditions, the time ratio is the reciprocal of the rate ratio.

References & reading

Our explanations are written for ChemistryCalc. Read how we build and check our tools. These calculations are educational estimates where the underlying model requires assumptions.